Django admin inline foreign key My current code is: class RankingInline(admin. 13. e, if a model A has a foreign-key to B, and also to C, and C has a foreign-key to B, and we want to ensure an A only refers to a C that refers to the same B as A does, the query needs to know about A->B, which it doesn't. The problem is that the Sleep model does not have a ForeignKey to Diary (instead, the relation is implicit by the use of dates). class UserAdmin(admin. – Feb 1, 2012 · class NoticeInline(admin. Display a read-only GenericForeignKey value in Is this possible? I haven't been able to use inlines, as my foreign key relationship is 'backwards' from what inline allows. TabularInline): model = Notice extra = 9 class WhenAdmin(admin. contrib import admin class BookInline(admin. 1. day. ModelAdmin): inlines = [ BookInline, ] Share Improve this answer Nov 8, 2012 · I'm trying to access a field of a foreign key within a Tabular Inline in the Django Admin. ModelAdmin): inlines = [ UserAdmin, ContactAdmin ] Jul 12, 2024 · In this tutorial, we’ll cover how to use TabularInline and StackedInline with detailed examples. ModelAdmin): inlines = [ BookInline, ] list_display = ['author_id', 'author_name', 'books', 'author_status . TabularInline): model = Book fields = ['title', 'id', 'status'] readonly_fields = ['id', 'status'] extra = 1 admin. ModelAdmin): inlines = [ BookInline, ] list_display = ['author_id', 'author_name', 'books', 'author_status If a model has multiple foreign keys pointing to the same parent model, Django’s admin requires you to explicitly specify which foreign key to use for inlines. TabularInline): model = Book class AuthorAdmin(admin. But your admin code should be as follows: class PhotoInline(admin. My problem is the same as that explained in this question (Django admin inline display but foreign key has opposite relation) but I cannot refactor my models as suggested in that answer. ModelAdmin): list_display = ('display_name','user_email') inlines = [PhotoInline] May 2, 2014 · from django. The inline model should be having a ForeignKey to the parent model. site. The admin is enabled in the default project template used by startproject. StackedInline): model = User class ContactAdmin(admin. GenericForeignKey and Admin in Django. StackedInline): model = Contact class UserProfileAdmin(admin. If you’re not using the default project template, here are the requirements: Jun 27, 2011 · Yes, you can do that using the inline admin system. Despite my best efforts I can't seem to get it working. class BookInline(admin. ModelAdmin): inlines = [ BookInline, ] list_display = ['author_id', 'author_name', 'books', 'author_status The inline model should be having a ForeignKey to the parent model. ModelAdmin): list_display = ('display_name','user_email') inlines = [PhotoInline] In this document we discuss how to activate, use, and customize Django’s admin interface. If you’re not using the default project template, here are the requirements: Jul 12, 2024 · In this tutorial, we’ll cover how to use TabularInline and StackedInline with detailed examples. Oct 15, 2013 · Django Admin Inline objects. I. register(Author, AuthorAdmin) class AuthorAdmin(admin. prints out as [<User: someone>, <User: someoneelse>] inlines = [NoticeInline] #but i want the User Jun 30, 2014 · How can I have Django generate a form for submitting Resumes where users can type in their university name and major? All four of which would be used to create new entries in their respective databases (2 in Universities, 2 in Majors) before saving the new resume similar to how the inline formset example works for a singular foreign key. This doesn't help as the query that runs in the limit_choices_to has no reference to the "parent class". Apr 14, 2023 · For that I implemented tabular inline. StackedInline): model = Photo class AuthorAdmin(admin. ModelAdmin): list_display = ('display_name','user_email') inlines = [PhotoInline] Jun 20, 2017 · I want my Diary model admin to display an inline for Sleep models that have start_time equal to the same day as Diary. In this document we discuss how to activate, use, and customize Django’s admin interface. Django inline admin classes (TabularInline and StackedInline) allow us to add related models Jul 15, 2020 · Recently a client asked me to experiment with implementing an admin inline view for a third party app where records are linked via natural keys but no explicit foreign key relationship exists between models. To get Photo as inline in Author your models code is fine. Is there any other way? The inline model should be having a ForeignKey to the parent model. Add inline model to django admin site. For example: to_person = Jan 17, 2024 · The inline model should be having a ForeignKey to the parent model. ModelAdmin): list_display = ('Date', ) readonly_fields = ('getteamresult', ) #this is to make clear i have access to what i want and i can display it. 22. epmde kwimt jbcft kxeaa cigjf uwyjcg ibvwygz krt avezj ozbvjl